2t=2.5t^2

Solution for 2t=2.5t^2 equation:

2t=2.5t^2

We move all terms to the left:

2t-(2.5t^2)=0

We get rid of parentheses

-2.5t^2+2t=0

a = -2.5; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-2.5)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-2.5}=\frac{-4}{-5}
=4/5
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-2.5}=\frac{0}{-5}
=0
$